Through a step-by-step process, calculate TFIDF for the given corpus:

**Document 1:** To the swinging and the ringing

**Document 2:** of the bells, bells, bells

**Document 3: **Of the bells, bells, bells, bells

**Document 4:** Bells, bells, bells

**Document 5:** To the rhyming and the chiming of the bells.

Topic | Natural Language Processing (AI Domain) |

Type | Short answer type |

Class | 10 |

**Step 1: Create document vectors for the given documents (Term Frequency Table):-**

To |
The |
Swinging |
and |
ringing |
of |
bells |
rhyming |
chiming |

1 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 |

0 | 1 | 0 | 0 | 0 | 1 | 3 | 0 | 0 |

0 | 1 | 0 | 0 | 0 | 1 | 4 | 0 | 0 |

0 | 0 | 0 | 0 | 0 | 0 | 3 | 0 | 0 |

1 | 1 | 0 | 1 | 0 | 1 | 1 | 1 | 1 |

**Step 2: Record the occurrence of the word in the document using the term frequency table (Document Frequency Table):-**

To |
The |
swinging |
and |
ringing |
of |
bells |
rhyming |
chiming |

2 | 4 | 1 | 2 | 1 | 3 | 11 | 1 | 1 |

**Step 3: Draw the inverse document frequency table wherein, we need to put the document frequency in the denominator while the total number of documents is the numerator. Here, the total number of documents is 5, hence inverse document frequency becomes:-**

To |
The |
swinging |
and |
ringing |
of |
bells |
rhyming |
chiming |

5/2 | 5/4 | 5/1 | 5/2 | 5/1 | 5/3 | 5/11 | 5/1 | 5/1 |

**Step 4: The formula of TFIDF for any word W becomes: TFIDF(W) = TF(W) * log (IDF(W)):-**

To |
the |
swinging |
and |
ringing |
of |
bells |
rhyming |
chiming |

1*log(5/2) | 1*log(5/4) | 1*log(5/1) | 1*log(5/2) | 1*log(5/1) | 0*log(5/3) | 0*log(5/11) | 0*log(5/1) | 0*log(5/1) |

0*log(5/2) | 1*log(5/4) | 0*log(5/1) | 0*log(5/2) | 0*log(5/1) | 1*log(5/3) | 3*log(5/11) | 0*log(5/1) | 0*log(5/1) |

0*log(5/2) | 1*log(5/4) | 0*log(5/1) | 0*log(5/2) | 0*log(5/1) | 1*log(5/3) | 4*log(5/11) | 0*log(5/1) | 0*log(5/1) |

0*log(5/2) | 0*log(5/4) | 0*log(5/1) | 0*log(5/2) | 0*log(5/1) | 0*log(5/3) | 3*log(5/11) | 0*log(5/1) | 0*log(5/1) |

1*log(5/2) | 1*log(5/4) | 0*log(5/1) | 1*log(5/2) | 0*log(5/1) | 1*log(5/3) | 1*log(5/11) | 0*log(5/1) | 0*log(5/1) |

Study more about **Natural Language Processing** at __Natural Language Processing Class 10__